Here is an interesting long-winded disclaimer by him:
http://fairmodel.econ.yale.edu/vote2004/med0704.htm"Given the current prediction of the equation that Bush will get over 57 percent of the two-party vote, does this mean that a Bush victory is a sure thing? The answer is no. First, the prediction is based on a particular set of economic forecasts (the current forecasts from my economic model), and if the economy does not do as well as this set says, the vote prediction for Bush will go down. Second, even if the equation is correctly specified, it makes on average an error of about 2.4 percentage points each election (called the "standard error"). Third, the equation may be misspecified. This is where the pitfalls come in.
Let me focus a bit on some possible pitfalls. Regression analysis assumes in the present context that the structure of voting behavior in the future will be like it has been in the past---as it has been estimated using the historical data back to 1916. One can never rule out a sudden shift of structure that makes this assumption wrong. For example, the Bush administration has made many large changes in foreign policy, social policy, and environmental policy, and it may be that these changes are so large that voters radically change their voting behavior. Perhaps voters now look much more at foreign, social, and environmental policies than they did in the past and less at how the economy is doing.
Another possible pitfall is that the equation is misspecified because it does not have a job growth variable in it, only an output growth variable. Historically output growth and job growth are so highly correlated that very similar estimates are obtained using either. They are too highly correlated for one to be able to estimate separate effects. If in 2004 output growth is fairly good, but job growth is not, this would lead the equation to be off if job growth is in fact more important in voters' minds than output growth.
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If you experiment on the site with alternative vote predictions, you will see that no realistic economic values can bring the predicted vote share to even about 53 percent. (Remember that there is only one quarter, 2004:3, for which actual economic data are not available.) This means, given the standard error of 2.4, that if the equation is correctly specified, the probability that Bush loses is very small. The bottom line is that the equation has to be misspecified in order for Bush to lose. And this is where the pitfalls come in. Regression analysis can only take us so far; possible pitfalls are always lurking.
Finally, a point about me as a social scientist trying to explain behavior versus me as a citizen. As a social scientist I am trying to do the best I can explaining the percentage share of the two-party vote. In this capacity I don't care who wins or loses, but how close the equation comes to explaining the actual share. If the actual share is 51 percent and the equation predicts 49 percent, this is better than if the actual share is 57 percent and the equation predicts 53 percent. Also, I shouldn't let my political views affect my scientific work. This is an exercise in trying to explain behavior, not shape it. As a citizen, however, I obviously care who wins or loses.
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