Doesn't this further splitting of the R votes give the D's a chance to get Jeffries in?

[Cuthbert Allgood]

If they do they math right, the last 6 or so Dems could not vote and Jeffries would have the majority.

[SCantiGOP]

1. I heard this discussed

If they could pull that off, then the Republican majority would have to vote for the rules, in which case they would allow his removal.

[Cuthbert Allgood]

7. So then they need to do that, I guess.

Just further evidence of their clown show.

[SCantiGOP]

21. I don't disagree

but I think their current strategy of just sitting back and letting them act like an ungovernable band of idiots is paying dividends.

[Cattledog]

2. He'd need 218 votes for a majority in the House.

Possible with less but highly unlikely.

[Cuthbert Allgood]

8. Not if people don't vote.

He needs the majority of the votes cast.

[Trumpdumper]

3. You'd need R's not to vote to decrease the denominator in the right way. The D's all need to vote.

[Cuthbert Allgood]

9. Not true.

You just have to do the math right so that Jeffries gets the majority. It wasn't possible with yesterday's votes, but with them further splitting, the math is doable.

[tritsofme]

14. The math is the same, there are still 212 Democratic votes

It would still take 12 Republicans to vote present, regardless of how they split, for 212 to make a majority.

[Cuthbert Allgood]

15. The votes for McCarthy was only split with Donalds. Had it been split more

than the D's could bring the amount down to get the majority.

[tritsofme]

18. It doesn't matter if Republicans split down the middle, the math doesn't change.

It still would take 12 Republicans either not showing up or voting present for Jeffries’ 212 votes to constitute a majority.

[ZonkerHarris]

4. 218 to win. We do not have 218 in any way shape or form.

[Cuthbert Allgood]

10. Majority of votes cast to win. Not 218.

That's why the Rs were asking if some Ds would not vote to give McCarthy the win yesterday.

[LiberalFighter]

5. All Dems would need to vote for Jeffries. It would require some R's voting Present.

[RockRaven]

6. Nope. Think about the math for a second. A vote for Jeffries adds one to the numerator and

the denominator. That always moves his needle up, no matter how the other votes have been split, and his needle needs to get over 50%.

[Cuthbert Allgood]

11. He needs the majority of the votes cast, not a hard 218.

The math is doable if McCarthy is losing like 50 R votes to other people.

[Orangepeel]

12. He'd need the Rs not to vote. Voting for other people doesn't help

the Rs not voting for McCarthy want to cause chaos. They don't want to help the Democrats.

[Cuthbert Allgood]

13. I get that's what they want, but if my math is correct, we would need 20 no votes

to give Jeffries the majority. Now, I fully realize that the R's should understand that is what they are doing when the 20th to the last D voted present, but they have shown to be stupid.

But the math and the rules work.

[RockRaven]

20. The OP asked about *Democrats* abstaining from voting, that is what my answer addresses.

And nowhere did I cite any specific vote number.

[wryter2000]

16. If a Dem doesn't vote

You lose half a number in the denominator, but you lose a whole number in the numerator. Any Dem not voting is a loss for Jeffries.

[Cuthbert Allgood]

17. UPDATE ON THE MATH: Only Donalds got votes, so it won't work

But if 20 people voted for Donalds and 20 people voted for Jordan, it becomes very possible for Dems voting present to get Jeffries the majority. Seems like the R's aren't as stupid as they seem.

[onenote]

19. Pretty sure the same people who voted for Donalds

Voted for Jordan. There aren’t 40 repubs who voted vs McCarthy

[Emile]

22. Only if McCarthy voters get pissed and throw

enough votes to Jefferies and that ain't gonna happen.