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(39,376 posts)OnDoutside
(20,868 posts)Horse = 10
Hshoe = 4
Boot = 2
Boot + Horse x Hshoe = ??
BOMDAS precedence
Boot + (Horse x Hshoe) = ??
2 + (10 x 4) = 42
Liberal_in_LA
(44,397 posts)OnDoutside
(20,868 posts)Liberal_in_LA
(44,397 posts)OnDoutside
(20,868 posts)Liberal_in_LA
(44,397 posts)TreasonousBastard
(43,049 posts)Liberal_in_LA
(44,397 posts)TreasonousBastard
(43,049 posts)Liberal_in_LA
(44,397 posts)jberryhill
(62,444 posts)Of what value is one boot?
pintobean
(18,101 posts)jberryhill
(62,444 posts)pintobean
(18,101 posts)jberryhill
(62,444 posts)If you can't get out of the house fast enough with the bread bags on, then there's just no hope.
baldguy
(36,649 posts)randome
(34,845 posts)[hr][font color="blue"][center]"If you're bored then you're boring." -Harvey Danger[/center][/font][hr]
randome
(34,845 posts)If it's 1 + (10 * 4), then 41?
[hr][font color="blue"][center]"If you're bored then you're boring." -Harvey Danger[/center][/font][hr]
TheBlackAdder
(29,981 posts).
Dang. Horseshoes are 2.
.
kentuck
(115,406 posts)TheBlackAdder
(29,981 posts)pinboy3niner
(53,339 posts)Liberal_in_LA
(44,397 posts)pinboy3niner
(53,339 posts)Liberal_in_LA
(44,397 posts)pintobean
(18,101 posts)Liberal_in_LA
(44,397 posts)lumberjack_jeff
(33,224 posts)But in fairness, I didn't get it right until I read this thread.
The King of Prussia
(751 posts)21
Liberal_in_LA
(44,397 posts)yesphan
(1,604 posts)Liberal_in_LA
(44,397 posts)Dale Neiburg
(797 posts)Horse = 10
One horseshoe = 2
One boot=1.
Liberal_in_LA
(44,397 posts)Response to Dale Neiburg (Reply #15)
randome This message was self-deleted by its author.
magicnpoetry
(45 posts)Donkees
(33,706 posts)MicaelS
(8,747 posts)Now I see it's 21.
Deuce
(960 posts)11 Bravo
(24,310 posts)Liberal_in_LA
(44,397 posts)11 Bravo
(24,310 posts)mcar
(46,055 posts)mcar
(46,055 posts)Is 22 right?
Buzz Clik
(38,437 posts)multiplication takes precedence over addition; that is, do the multiplication first.
mcar
(46,055 posts)So we've got 21 then.
mcar
(46,055 posts)Maeve
(43,456 posts)My Dear Aunt Sally--multiply, divide, add, subtract! I've spent 40 years forgetting that voice....

Maeve
(43,456 posts)Liberal_in_LA
(44,397 posts)landolfi
(234 posts)What do I win?
landolfi
(234 posts)TDale313
(7,822 posts)Liberal_in_LA
(44,397 posts)TDale313
(7,822 posts)Grassy Knoll
(10,118 posts)*21*
OilemFirchen
(7,288 posts)Is the horse alive?
Useless without context.
pintobean
(18,101 posts)brooklynite
(96,882 posts)Horse=10
Horseshoe=2
Boots=0
0+10=10
10*2=2 (absent parentheses, the multiplier applies to the prior number which is a function of the sum)
Nuclear Unicorn
(19,497 posts)H + H + H + = 30
= 3H = 30
= 30 / 3
H = 10
H + S + S = 18
= 10 + S + S
= 10 + 2S
= 2S = 18 - 10
= 2S = 8
= 8 / 2
S = 4
S - B = 2
= 4 - B = 2
B = 4 - 2
B = 2
2 + 10 x 4 =
= 2 + (10 x 4) = (order of operations PEMDAS)
= 2 + 40
= 42
DrDan
(20,411 posts)ArtD48
(150 posts)Line 1 tells us "Horse + Horse + Horse = 30" so Horse = 10
Line 2 says "10 + Horseshoe + Horseshoe = 18" so Horseshoe = 4
Line 3 says "Horseshoe - Boot = 2" so Boot = 2
So line 4 becomes "2 + 10 * 4"
You multiply before you add so the answer is 42
LeftofObama
(4,243 posts)bigbrother05
(5,995 posts)one boot + one horse X one horseshoe = 1 + 10 X 2 = 21
missed that it's half of the pair in the final equation
GummyBearz
(2,931 posts)That will fix your problems.
Line 4 is "1 + (10 * 2)" = 21
jberryhill
(62,444 posts)Adjacent symbols is multiplication, not addition.
Author of the problem does not understand how math works.
For BootBoot to equal 2, then Boot = sqrt(2)
GummyBearz
(2,931 posts)I think we agree from line 1 a horse is 10
In line 2, there are 4 horseshoes, in 2 groups of 2. 10 + (2+2) + (2+2) = 18
In line 3, there are 2 horseshoes in 1 group of 2 being substracted by 2 boots. (2+2) - (1+1) = 2
Therefore, boots = 1, horseshoes = 2.
Line four shows 1 boot and 1 horseshoe. Not 2 of each
on edit. If i have 2 apples in my hand, it is 1+1. Yes they are adjacent to eachother, but they don't multiply...
jberryhill
(62,444 posts)XY is not "
Let's say "U" is a horseshoe, and it has a value of N
UU is not "N+N"
The overall problem suggests, since the symbols appear as either two adjacent ones, or a single one, that the individual symbols have value.
So if two horseshoes equals two, i.e. UU = 2
Then the value of U, standing alone, is 1.7071068.... the square root of two.
GummyBearz
(2,931 posts)In your world, if you had 2 horseshoes in a hand, and then put them in separate hands, you would have sqrt(2) horseshoe in each hand. Interesting world to live in, but not the real one.
jberryhill
(62,444 posts)You have fallen victim to the treachery of images:

And in your world, what is one boot worth?
Better than none but half as good as 2. Next time you buy 2 apples pay the cashier 2*sqrt(2)*cost per Apple. They can use the extra $
jberryhill
(62,444 posts)You are confusing a symbol of a thing with the thing itself.
Let me back up a moment.
Is this an apple:

Orrex
(67,111 posts)GummyBearz
(2,931 posts)jberryhill
(62,444 posts)Then you either have 8, 16, or 44, depending on the rules by which you are translating the drawings, into symbols, and then to numbers.
How much is this horse worth:

LAGC
(5,330 posts)lumberjack_jeff
(33,224 posts)Two boots is Boot+Boot in much the same way that a dozen eggs doesn't equal 1^12 eggs.
Nuclear Unicorn
(19,497 posts)unblock
(56,198 posts)i know the answer is meant to be 21, but that requires some assumptions.
strictly speaking, the final question involves symbols that are not defined.
jberryhill
(62,444 posts)Because, oh, no reason.
unblock
(56,198 posts)one horseshoe could mean anything.
jberryhill
(62,444 posts)You are going to tell me that BootBoot = 2, and Boot does not then equal the square root of two?
unblock
(56,198 posts)could be anything, in fact.
jberryhill
(62,444 posts)
unblock
(56,198 posts)kentuck
(115,406 posts)Now we're getting into geometry.
jberryhill
(62,444 posts)A pair of boots is valued at 2.
The last line has a single boot.
If the idea is that you are supposed to assume that "one boot" = 1, then that is an unsupported assumption.
You might just as well assume that a single boot is worthless.
Is "half a horse" worth 5? No, half a horse is a lifeless carcass.
Likewise, a broken horseshoe would be worthless.
As worthless as a single boot.
pintobean
(18,101 posts)Logic should indicate that once direct representation of the images doesn't apply, they must be symbols.
randome
(34,845 posts)Get off your high horse! No...wait, I mean...ahhh!
[hr][font color="blue"][center]"If you're bored then you're boring." -Harvey Danger[/center][/font][hr]
Dr. Strange
(26,058 posts)Now you're just beating a dead horse.
aikoaiko
(34,214 posts)If horse = 10, horseshoehorseshoe = 4, and bootboot = 2, but then boot (1) + ( horse (10) x horseshoe (2) = 21, doesn't that violate the mathematical standard of two numbers next to each other without an operator implying multiplication in the equations with bootboot?
eppur_se_muova
(41,938 posts)think of Roman numerals: IIII = four
There are a few assumptions in the presentation of this problem, as others have pointed out.
jberryhill
(62,444 posts)XY is X * Y, not X + Y. Oh, we aren't supposed to use Algebraic rules, we are supposed to be Ancient Romans now?
The assumption that one boot has half the value of two boots is not at all obvious. Who wants one boot?
This is a situation I personally ran into with my own kid.
The teacher kept marking him wrong for problems like this:
"Amy has three cookies. Bill has four cookies. If Amy gives you one and a half cookies, and Bill gives you two and a half cookies, how many cookies do you have?"
My kids answer was "Three cookies and two half cookies."
Because, WTF? If I give you two half cookies, you do not have one cookie. Are you supposed to glue the two halves back together and call it a cookie?
Under-determined math problems with "oh yeah, well, you are supposed to assume..." drive me bananas.
You give someone a choice between a whole, undamaged cookie, and two broken half cookies, and see which one they want.
3catwoman3
(29,404 posts)...very smart, obviously. I am impressed.
Codeine
(25,586 posts)eppur_se_muova
(41,938 posts)shoe=1
horse=10
horseshoe=2 (not = horse*shoe, which seems an awkward choice of notation)
Multiplication takes precedence over addition, so 1 + (10 x 2) = 21
DawgHouse
(4,019 posts)jack_krass
(1,009 posts)Horse=10
Horseshoe=4
Boot=2
2+(10*4)=42
closeupready
(29,503 posts)I wish someone would explain how they're getting 21.
Liberal_in_LA
(44,397 posts)TexasBushwhacker
(21,202 posts)Good old "order of operations".
Person 2713
(3,263 posts)so I am wrong on my guess
No I do not use much math in daily work
tonyt53
(5,737 posts)rock
(13,218 posts)Coyotl
(15,262 posts)DrDan
(20,411 posts)earthshine
(1,642 posts)Substitute familiar symbols like X, Y, Z for horses and shoes.
jberryhill
(62,444 posts)Does it mean X+X or X*X?
If you are saying "substitute symbols", then:
If U = 1, do you mean UU=1 or UU = 11 or UU = 2?
Because if we are using normal algebraic rules, UU = 1 for U = 1.
Egnever
(21,506 posts)that said the xx-yy=2 line makes the addition seem implicit because it doesn't really work otherwise.
I would never read it any other way than you did. The pictures changing threw me though as I didn't notice that.
pintobean
(18,101 posts)earthshine
(1,642 posts)Coyotl
(15,262 posts)You assume nothing when doing algebra and we don't use horseshoes.
earthshine
(1,642 posts)In this case, one assumption is the tautology that one horseshoe is equal to another horseshoe (a=a), even if in a different equation in the system.
The purpose of algebra, or symbolic logic for that matter, is to reduce things with human-ascribed meaning to a set of symbols that can be manipulated based on a consistent set of rules.
The use of any particular symbols like X and Y to represent variables is not set in stone. The symbols can be anything.
QED
Egnever
(21,506 posts)44
wups not so easy forgot order of operations. 42
Hah also did not notice only one horse shoe on last line.
So in that case it becomes 22
last edit and now noticing one boot instead of two the images are tricky
That said I would go with 21 only because it does not work any other way. However I agree with Jberry when he said xx implies multiplication not addition.
That said the xx-yy= 2 makes the addition implicit since it doesn't work otherwise if x = 2. Poorly designed question IMHO and relies on manipulation of standard practices to achieve it's goal.
jberryhill
(62,444 posts)LAGC
(5,330 posts)jberryhill
(62,444 posts)But since a horse is not an ass, then you cannot kick a horse in the ass unless it is a mule.
TheBlackAdder
(29,981 posts).
Dang. Horseshoes are 2.
.
lame54
(39,758 posts)on edit
did the order of operation wrong
Liberal_in_LA
(44,397 posts)lame54
(39,758 posts)a horse equals 10
a horse-shoe equals 4
a boot equals 2
4x10+2 =42
Shrike47
(6,913 posts)One boot is half of 2 boots, etc.l
This problem demands assumptions.
MowCowWhoHow III
(2,103 posts)Easy peasy solved in the head.
lame54
(39,758 posts)Waldorf
(654 posts)edit: 21. Thought I was smart but didn't pay attention to only one boot and horseshoe.
Xyzse
(8,217 posts)H+H+H = 30 (H=10)
H(10)+HS+HS = 18 : HS+HS = 8 : (HS = 4)
HS(4) - B = 2 :: (B = 2)
B(2) + H(10) x HS(4)
B(2) + 40 = 42
Answer to Life, the Universe and Everything!
msanthrope
(37,549 posts)stopbush
(24,808 posts)ret5hd
(22,502 posts)rather than type "21".
jberryhill
(62,444 posts)martin mike
(82 posts)or blue and black, take your pick.
Tikki
(15,140 posts)Tikki
marle35
(172 posts)No one getting a different number has yet explained (in detail) their method. I remain confused by this thread.
Response #120 explains why it's 42.
Liberal_in_LA
(44,397 posts)GreenEyedLefty
(2,116 posts)Liberal_in_LA
(44,397 posts)3 X horses = 30, horse = 10
Horse plus 2 X shoes = 18, implies 10 plus 2 X shoes = 18, implies shoes = 4
Shoes minus boots = 2 implies 4 boots = 2, so boots = 2
If boots = 2, one boot = 1 < tricky step
If shoes = 4, one shoe = 2 < tricky step
So boot plus horse X shoe = 1 + 10 X 2 = 1 + (10 X 2) = 1 + 20 = 21
rug
(82,333 posts)Coyotl
(15,262 posts)We have no clue regarding the value of two of the symbols in the bottom line. They could mean anything. Is one boot 1,000 or 1?
Basically, this is a really lame exercise.
DCBob
(24,689 posts)lonestarnot
(77,097 posts)Liberal Veteran
(22,239 posts)nolabels
(13,133 posts)Four and twenty
lamp_shade
(15,481 posts)alittlelark
(19,139 posts)WDIM
(1,662 posts)DCBob
(24,689 posts)Assuming the value is one for one boot because the two boot image is two is assuming too much. Same with the single horseshoe.
The other images we know values for dont work that way.
One horse is 10. Two horsehoes are 4. There is no numeric consistency implied or defined regarding the number of elements in an image.
Liberal_in_LA
(44,397 posts)DCBob
(24,689 posts)"Each element in each image represents a value and the values are unique by type of element."
That would have eliminated any ambiguity.
baldguy
(36,649 posts)given:
horse + horse + horse = 30
horse + pair of horseshoes + pair of horseshoes = 18
pair of horseshoes - pair of boots = 2
boot + horse x horseshoe = ??
therefore:
horse + horse + horse = 30
3(horse) = 30
3(horse)/3 = 30/3
horse = 10
horse + pair of horseshoes + pair of horseshoes = 18
10 + 2(horseshoes) + 2(horseshoes) = 18
4(horseshoes) = 8
4(horseshoes)/4 = 8/4
horseshoe = 2
pair of horseshoes - pair of boots = 2
2(horseshoes) - 2(boots) = 2
2(2) - 2(boots) = 2
4 - 2(boots) = 2
- 2(boots) = - 6
2(boots) = 6
2(boots)/2 = 6/2
boot = 3
boot + horse x horseshoe = ??
boot + (horse x horseshoe) = ??
boot = 3
horse = 10
horseshoe = 2
3 + (10 x 2) = ??
3 + (20) = ??
23 = ??
Liberal_in_LA
(44,397 posts)BlueStateLib
(937 posts)horse = 10
2 horseshoe = 4
2 boots = 2
Liberal_in_LA
(44,397 posts)Lady Freedom Returns
(14,198 posts)JustABozoOnThisBus
(24,681 posts)But, I don't think my dog is much smarter than Trump, so there's that.
VOX
(22,976 posts)Horse = 10
Horseshoe pair = 4
Hotshot single = 2
Boot pair = 2
Boot single = 1
1 (Boot single) + 10 (Horse) X 2 (Horshoe single) = 21
