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2016 Postmortem

George II

(67,782 posts) Mon May 30, 2016, 10:06 PM May 2016

Here's a curious item - Sanders' pledged delegates AND superdelegates don't even equal.....

....Clinton's pledged delegates alone! Noticed this when I was looking at the current delegate count here:

https://www.google.com/search?q=democratic+delegate+count&rlz=1C1RNNN_enUS356&oq=democratic+d&aqs=chrome.4.69i59j69i60l3j69i59j0.8712j0j4&sourceid=chrome&ie=UTF-8#eob=m.09c7w0/D/5/short/m.09c7w0/

3 replies

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Here's a curious item - Sanders' pledged delegates AND superdelegates don't even equal..... (Original Post) George II May 2016 OP

But, the way their math goes, it means Sanders wins.....LOL Trust Buster May 2016 #1

You're right - I forgot that all 714 superdelegates are going to vote for her. Sorry! George II May 2016 #2

Certainly it doesn't look good, or even hopeful, for Sanders Tal Vez May 2016 #3

Trust Buster

(7,299 posts)

1. But, the way their math goes, it means Sanders wins.....LOL

Reply to George II (Original post)

Mon May 30, 2016, 10:08 PM

May 2016

George II

(67,782 posts)

2. You're right - I forgot that all 714 superdelegates are going to vote for her. Sorry!

Reply to Trust Buster (Reply #1)

Mon May 30, 2016, 10:14 PM

May 2016

Tal Vez

(660 posts)

3. Certainly it doesn't look good, or even hopeful, for Sanders

Reply to George II (Original post)

Mon May 30, 2016, 10:21 PM

May 2016

but I believe that his point is that the loyalty of uncommitted delegates belongs to no one before they actually vote at the convention. And, if I understand him correctly, he doesn't believe that uncommitted delegates should make any promises before the convention or (as was often the case here) before Sanders even declared his candidacy. And, while that may sound good, it is a bit unrealistic to hope that these most political of delegates will not be making deals and commitments whenever they think it best for themselves.

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