If you're having math problems, I feel bad for you, son...

[Jim__]

12. As simply as it can be put, your statement is in direct contradiction to a Zermelo-Fraenkel axiom.

You know, Zermelo-Fraenkel:

In mathematics, Zermelo–Fraenkel set theory with the axiom of choice, named after mathematicians Ernst Zermelo and Abraham Fraenkel and commonly abbreviated ZFC, is one of several axiomatic systems that were proposed in the early twentieth century to formulate a theory of sets without the paradoxes of naive set theory such as Russell's paradox. Specifically, ZFC does not allow unrestricted comprehension. Today ZFC is the standard form of axiomatic set theory and as such is the most common foundation of mathematics.

From your last post:

But lets suppose instead, my integer is defined as

m = 1+1+1+... (to infinity)

can you add 1 to this infinitely long integer and make it larger? Its value is already infinite. Can you get a larger number with infinity plus 1? No.

You don't understand the mathematical concept of infinity. Yes, you can always add 1 to an integer. The Zermelo-Fraenkel Axiom of Infinity:

Let S(x) abbreviate x ∪ {x}, where x is some set. Then there exists a set X such that the empty set ∅ is a member of X and, whenever a set y is a member of X, then S(y) is also a member of X.

∃ X ( ∅ ∊ X ∧ ∀ y ( y ∊ X => S(y) ∊ X))