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Joe BidenCongratulations to our presumptive Democratic nominee, Joe Biden!

Response to brooklynite (Original post)

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Suspect Bloomberg's long strategy is to really go for it - only if JB gets undercut enough. empedocles Jan 2020 #1
Sanders will do whatever he can to scuttle the party if it isn't him. We've already seen that movie. brush Jan 2020 #2
Agreed wiley Jan 2020 #3
So you're saying that only Sanders will follow a democratic process? FBaggins Jan 2020 #4
Yeah, all they care about is that "good of the country" nonsense LongtimeAZDem Jan 2020 #5
Interesting FBaggins Jan 2020 #8
No, most Democrats go all in for the notion of having a Democrat win the election LongtimeAZDem Jan 2020 #9
They are in no sense contradicatory things FBaggins Jan 2020 #10
Again, no. This is not a national referendum; it is a political party choosing the best candidate LongtimeAZDem Jan 2020 #11
Perhaps you should read the OP before commenting on a thread? FBaggins Jan 2020 #13
Candidates bow out and throw their support to others all the time. Is this your first election? LongtimeAZDem Jan 2020 #14
Lol... that clearly isn't what the OP is talking about. FBaggins Jan 2020 #15
Sure it is; there's nothing in the rules that prevent them from doing preciely that, and LongtimeAZDem Jan 2020 #16
Again... you should read the OP FBaggins Jan 2020 #17
Nothing can "fix" it if Sanders is determined to disrupt the process; however, a deal like the OP LongtimeAZDem Jan 2020 #19
Again... you keep confusing "the process" with this new "how do we avoid Sanders?" 'process' FBaggins Jan 2020 #22
Stunning extremes BS supporters go to trying to counter the spoiler perception and cast emmaverybo Jan 2020 #28
See Post #2 brush Jan 2020 #18
I'm not interested in violating the "Don't keep fighting the last primary" rule FBaggins Jan 2020 #21
Depends how the delegate counts look. DanTex Jan 2020 #6
Any "deals" must respect the candidate with the plurality of delegates. bluewater Jan 2020 #20
plurality means more people do not want him/her than want him/her nt msongs Jan 2020 #33
That would be true for a Biden plurality, right? bluewater Jan 2020 #35
Post removed Post removed Jan 2020 #7
well, now. That was a little uncalled for. wyldwolf Jan 2020 #12
Allow me to elaborate... brooklynite Jan 2020 #23
ANY "deal" will have to respect the candidate with the plurality of delegates bluewater Jan 2020 #24
Exactly +1 LongtimeAZDem Jan 2020 #25
A point well taken and supported by past history. emmaverybo Jan 2020 #29
This message was self-deleted by its author pinkstarburst Jan 2020 #30
As Brooklynite said, Sanders having the most delegates is not the scanrio in question LongtimeAZDem Jan 2020 #32
My grandson is a saidsimplesimon Jan 2020 #26
The nominee WILL have a plurality of delegates...... getagrip_already Jan 2020 #27
Bloomberg, Buttegieg and Warren will be facing the problem of the delegate threshold. Aaron Pereira Jan 2020 #31
Terrible strategy, regardless how legal it is dbolski Jan 2020 #34
Superdelegates are there to represent the party. Democrats understand that. LongtimeAZDem Jan 2020 #36
When have they not? When they were petitioned by candidates to overturn ehrnst Feb 2020 #38
You are correct. Demsrule86 Jan 2020 #37
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