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In reply to the discussion: Can YOU solve it? [View all]

DCBob

(24,689 posts)
158. Cannot be solved. There is no value given or implied for the single boot or horseshoe images.
Thu Sep 8, 2016, 12:29 PM
Sep 2016

Assuming the value is one for one boot because the two boot image is two is assuming too much. Same with the single horseshoe.

The other images we know values for dont work that way.

One horse is 10. Two horsehoes are 4. There is no numeric consistency implied or defined regarding the number of elements in an image.

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Can YOU solve it? [View all] Liberal_in_LA Sep 2016 OP
I think I got it NightWatcher Sep 2016 #1
Yes, see in here OnDoutside Sep 2016 #2
No Liberal_in_LA Sep 2016 #3
I'm all ears ... please explain OnDoutside Sep 2016 #4
Look at formula again Liberal_in_LA Sep 2016 #6
Ah, 41 OnDoutside Sep 2016 #10
No Liberal_in_LA Sep 2016 #21
Why not? Why would 48 be a better answer? TreasonousBastard Sep 2016 #18
No Liberal_in_LA Sep 2016 #22
Never mind-- one boot one shoe... Aargh! TreasonousBastard Sep 2016 #24
... Liberal_in_LA Sep 2016 #32
One boot has no value jberryhill Sep 2016 #76
If it's raining, or snowing... pintobean Sep 2016 #85
No, then you get bread bags jberryhill Sep 2016 #86
Won't they melt from the fire? pintobean Sep 2016 #87
Ask Joni Ernst jberryhill Sep 2016 #125
Ah, the HHGG answer. baldguy Sep 2016 #91
1 + 10 x 4 = 44. randome Sep 2016 #5
No Liberal_in_LA Sep 2016 #7
Different calculators use different orders of precedence. randome Sep 2016 #20
No Liberal_in_LA Sep 2016 #28
PEMDAS = Paren, Exponent, Mult, Div, Add, Sub. 1 + 10 X 2 = 21. Same as 1 + (10 x 2) = 21. TheBlackAdder Sep 2016 #103
That does bring back the nightmares of freshman algebra. kentuck Sep 2016 #116
Sorry for that! TheBlackAdder Sep 2016 #132
22? pinboy3niner Sep 2016 #8
No Liberal_in_LA Sep 2016 #12
Ah! 1 + (10 x 2) = 21 :) pinboy3niner Sep 2016 #51
.. Liberal_in_LA Sep 2016 #109
21 pintobean Sep 2016 #9
.. Liberal_in_LA Sep 2016 #14
Agree. lumberjack_jeff Sep 2016 #147
If it's not 21 I'd like to know why. The King of Prussia Sep 2016 #11
.. Liberal_in_LA Sep 2016 #16
21 yesphan Sep 2016 #13
... Liberal_in_LA Sep 2016 #17
Total is 22 Dale Neiburg Sep 2016 #15
No..but close Liberal_in_LA Sep 2016 #19
This message was self-deleted by its author randome Sep 2016 #29
Yup magicnpoetry Sep 2016 #127
22 Donkees Sep 2016 #23
No Liberal_in_LA Sep 2016 #26
48 ....edit MicaelS Sep 2016 #25
.. Liberal_in_LA Sep 2016 #27
21... Deuce Sep 2016 #30
.. Liberal_in_LA Sep 2016 #34
11? (If I remember my order of operations correctly.) 11 Bravo Sep 2016 #31
No Liberal_in_LA Sep 2016 #37
I edited my response. Is 11 correct? 11 Bravo Sep 2016 #40
48 B2G Sep 2016 #33
No Liberal_in_LA Sep 2016 #35
22 mcar Sep 2016 #36
No Liberal_in_LA Sep 2016 #38
I just corrected mcar Sep 2016 #39
Remember the sequencing of math operators Buzz Clik Sep 2016 #44
I forgot that - math class was a long time ago! mcar Sep 2016 #47
! Buzz Clik Sep 2016 #49
My math teacher SO will be so proud! mcar Sep 2016 #50
God...now I hear my algebra teacher's voice! Maeve Sep 2016 #148
.. Buzz Clik Sep 2016 #153
That's her! eom Maeve Sep 2016 #159
Look at formula very carefully Liberal_in_LA Sep 2016 #45
11 landolfi Sep 2016 #41
Never mind, see this was attempted already. landolfi Sep 2016 #43
13? n/t TDale313 Sep 2016 #42
No Liberal_in_LA Sep 2016 #46
Oh, I see it now. 21. TDale313 Sep 2016 #59
0 U 8 1 2 Grassy Knoll Sep 2016 #48
Why are horseshoes worth more than boots? OilemFirchen Sep 2016 #52
They carry more weight. pintobean Sep 2016 #60
Answer: 20 brooklynite Sep 2016 #53
Horse = 10, Horseshoe = 4, Boot = 2 Nuclear Unicorn Sep 2016 #130
10, 2 and 1 so 21 DrDan Sep 2016 #54
Easy (42) ArtD48 Sep 2016 #55
That's EXACTLY how I see it: 42 LeftofObama Sep 2016 #61
pair horseshoes = 4: pair boots = 2 bigbrother05 Sep 2016 #62
Horseshoe = 2, boot = 1 GummyBearz Sep 2016 #65
If "boot = 1" and "Horseshoe = 2" then BootBoot equals one jberryhill Sep 2016 #83
Sorry GummyBearz Sep 2016 #90
Adjacent symbols implies multiplication, not addition jberryhill Sep 2016 #92
You are confusing the abstract with reality GummyBearz Sep 2016 #94
Those are symbols, not horseshoes jberryhill Sep 2016 #98
1 GummyBearz Sep 2016 #105
Next time I am buying apples, I will buy actual apples, and not poor drawings of them jberryhill Sep 2016 #106
This is not a pipe Orrex Sep 2016 #112
Put 2 of them next to eachother and tell me how many apples you have GummyBearz Sep 2016 #119
If the image of the apple is intended to signify, say, 4 jberryhill Sep 2016 #123
I knew someone was going to do this in this thread. LAGC Sep 2016 #133
What would BootBootBoot equal? lumberjack_jeff Sep 2016 #146
42 Nuclear Unicorn Sep 2016 #56
undefined. unblock Sep 2016 #57
And, apparently, two symbols adjacent is supposed to imply addition instead of multiplication jberryhill Sep 2016 #80
put the symbol '1' next to itself and you get, uh, eleven. unblock Sep 2016 #81
yes, but Boot = Sqrt(2) jberryhill Sep 2016 #84
could also be negative sqrt(2) unblock Sep 2016 #88
How about a quarterhorse? jberryhill Sep 2016 #89
mind. blown. unblock Sep 2016 #93
Damn! kentuck Sep 2016 #118
The problem is under-determined jberryhill Sep 2016 #58
How does one multiply a horse by a horseshoe? pintobean Sep 2016 #64
Oh, come on! Wear the boot on one foot and the horseshoe on the other! randome Sep 2016 #66
Well... Dr. Strange Sep 2016 #70
If the answer to the last equation is 21, isn't there a problem with the equation above it? aikoaiko Sep 2016 #63
Presumably, these are functioning as "tallies", like most early numeration systems used ... eppur_se_muova Sep 2016 #67
Correct, but that is not obvious from the presentation of the problem jberryhill Sep 2016 #78
Your kid is... 3catwoman3 Sep 2016 #160
Dammit. Tricksy visual. nt Codeine Sep 2016 #68
21 eppur_se_muova Sep 2016 #69
21 DawgHouse Sep 2016 #71
42 jack_krass Sep 2016 #72
+1 that's what I got. closeupready Sep 2016 #74
Me too marle35 Sep 2016 #79
look at the boots, look at the horseshoes. How many do you see in each equation. Liberal_in_LA Sep 2016 #108
21 TexasBushwhacker Sep 2016 #73
42 or maybe 48 oops now just saw the double horse shoe Person 2713 Sep 2016 #75
Eleventy-seven. Everybody knows that. tonyt53 Sep 2016 #77
97? rock Sep 2016 #82
No value stated for the symbol of one horseshoe. No solution without an assumption. Coyotl Sep 2016 #95
if you know the value of 4 horseshoes, then you know the value of one horseshoe DrDan Sep 2016 #96
This is algebra. Nothing more. earthshine Sep 2016 #97
Okay, so what, in your mind does "XX" mean? jberryhill Sep 2016 #101
Agreed this stands common practice on it's head Egnever Sep 2016 #107
XXX = Trojan horse, so XX means pintobean Sep 2016 #121
You make good points. It's not simple algebra, but some bastardization. nt earthshine Sep 2016 #124
I teach college algebra. Coyotl Sep 2016 #144
All formal logic system have both implicit and explicit assumptions. earthshine Sep 2016 #156
ok not easy Egnever Sep 2016 #99
It means "If you kick a horse in the ass, you are getting a horseshoe in your face" jberryhill Sep 2016 #100
That would be the only safe assumption here. LAGC Sep 2016 #134
Although, some migh argue that you can kick a horse, or you can kick an ass jberryhill Sep 2016 #135
... LAGC Sep 2016 #137
1 + 10 x 2 = 21. Multiplication before addition. (Shoe=1, Horse=10, Horseshoe=2) TheBlackAdder Sep 2016 #102
42... lame54 Sep 2016 #104
nope Liberal_in_LA Sep 2016 #110
Yes... lame54 Sep 2016 #111
Nope. 1 horse shoe does not equal 2 horse shoes. 1 boot does not equal 2 boots. Shrike47 Sep 2016 #113
21 - I was ready to solve simultaneous equations, but quickly realised no need to MowCowWhoHow III Sep 2016 #114
Ok - you got me - 21 - details details lame54 Sep 2016 #115
42. n/t Waldorf Sep 2016 #117
It's the answer to life, the universe and everything! 42 Xyzse Sep 2016 #120
21. nt msanthrope Sep 2016 #122
Who cares? stopbush Sep 2016 #126
Says the person that took the time to type "Who cares?"... ret5hd Sep 2016 #129
The person was not expressing a lack of caring, but canvassing for people who do jberryhill Sep 2016 #136
the dress is black and blue martin mike Sep 2016 #128
40 Tikki Sep 2016 #131
It's 42. marle35 Sep 2016 #138
look at all 4 formulas carefully. Line 3 has 1 boot rather than 2. line 4 has one horse shoe Liberal_in_LA Sep 2016 #140
42 GreenEyedLefty Sep 2016 #139
solution Liberal_in_LA Sep 2016 #142
18 KG Sep 2016 #141
807! rug Sep 2016 #143
There is no solution without defining the undefined symbols. Coyotl Sep 2016 #145
Correct. There is no value for 1 boot or 1 horseshoe so the last equation is unsolvable. DCBob Sep 2016 #157
Pile of horseshit? lonestarnot Sep 2016 #149
12 Liberal Veteran Sep 2016 #150
Something about smoking pot. nolabels Sep 2016 #151
22 lamp_shade Sep 2016 #152
I got 22....? alittlelark Sep 2016 #154
21 WDIM Sep 2016 #155
Cannot be solved. There is no value given or implied for the single boot or horseshoe images. DCBob Sep 2016 #158
Agreed but good algebra practice Liberal_in_LA Sep 2016 #162
Yes. It would have been better to add this.. DCBob Sep 2016 #170
23 baldguy Sep 2016 #161
Close Liberal_in_LA Sep 2016 #164
21 BlueStateLib Sep 2016 #163
Yes Liberal_in_LA Sep 2016 #165
44? Lady Freedom Returns Sep 2016 #166
My dog barked 48 times. So that must be the answer. JustABozoOnThisBus Sep 2016 #167
21 for certain... VOX Sep 2016 #168
44 Stinky The Clown Sep 2016 #169
Remember order of operations..... 21. NT Adrahil Sep 2016 #171
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